disconjugateとは 意味・読み方・使い方

語源

From dis- +‎ conjugate.

形容詞

disconjugate (not comparable)

1. (medicine) Operating independently; not joined in action.
   • 1994 June, Kyle A. Arnoldi, Lawrence Tychsen, “Prevalence of Intracranial Lesions in Children Presenting with Disconjugate Nystagmus (Spasmus Nutans)”, in Update on Strabismus and Pediatric Ophthalmology: Proceedings of the Joint ISA and AAPO&S Meeting, Vancouver, Canada, →ISBN:

     The disconjugate nystagmus, head titubation, and torticollis of spasmus nutans have been reported as indisinguishable from those associated with glioma of the anterior visual pathway.

   • 1999, R. John Leigh, David S. Zee, The Neurology of Eye Movements, →ISBN:

     In other words, the subject learned to preprogram intrasaccadic and postsaccadic disconjugate movements independent of any immediate disparity cues.

   • 2014, Erwin B Montgomery, Intraoperative Neurophysiological Monitoring for Deep Brain Stimulation, →ISBN:

     Absence of parallel movement of the eyes indicates disconjugate gaze disturbance (Figure 12.8).

2. (mathematics) Having at most one fewer zeros (including multiplicities) than the dimension of the problem space.
   • 2016, Alberto Cabada, Lorena Saavedra, “Constant sign Green's function for simply supported beam equation”, in arXiv‎:

     The aim of this paper consists on the study of the following fourth-order operator: \begin{equation}\label{Ec::T4} T[M]\,u(t)\equiv u^{(4)}(t)+p_1(t)\,u"'(t)+p_2(t)\,u"(t)+M\,u(t)\,,\ t\in I \equiv [a,b]\,, \end{equation} coupled with the two point boundary conditions: \begin{equation}\label{Ec::cf} u(a)=u(b)=u"(a)=u"(b)=0\,. \end{equation} So, we define the following space: \begin{equation}\label{Ec::esp} X=\left\lbrace u\in C^4(I)\quad\mid\quad u(a)=u(b)=u"(a)=u"(b)=0 \right\rbrace \,. \end{equation} Here ${\displaystyle p_{1}\in C^{3}(I)}$ and ${\displaystyle p_{2}\in C^{2}(I)}$. By assuming that the second order linear differential equation \begin{equation}\label{Ec::2or} L_2\, u(t)\equiv u"(t)+p_1(t)\,u'(t)+p_2(t)\,u(t)=0\,,\quad t\in I, \end{equation} is disconjugate on ${\displaystyle I}$, we characterize the parameter's set where the Green's function related to operator ${\displaystyle T[M]}$ in ${\displaystyle X}$ is of constant sign on ${\displaystyle I\times I}$.