disconjugateとは 意味・読み方・使い方

語源

From dis- +‎ conjugate.

形容詞

disconjugate (not comparable)

1. (medicine) Operating independently; not joined in action.
   • 1994 June, Kyle A. Arnoldi, Lawrence Tychsen, “Prevalence of Intracranial Lesions in Children Presenting with Disconjugate Nystagmus (Spasmus Nutans)”, in Update on Strabismus and Pediatric Ophthalmology: Proceedings of the Joint ISA and AAPO&S Meeting, Vancouver, Canada, →ISBN:

     The disconjugate nystagmus, head titubation, and torticollis of spasmus nutans have been reported as indisinguishable from those associated with glioma of the anterior visual pathway.

   • 1999, R. John Leigh, David S. Zee, The Neurology of Eye Movements, →ISBN:

     In other words, the subject learned to preprogram intrasaccadic and postsaccadic disconjugate movements independent of any immediate disparity cues.

   • 2014, Erwin B Montgomery, Intraoperative Neurophysiological Monitoring for Deep Brain Stimulation, →ISBN:

     Absence of parallel movement of the eyes indicates disconjugate gaze disturbance (Figure 12.8).

2. (mathematics) Having at most one fewer zeros (including multiplicities) than the dimension of the problem space.
   • 2016, Alberto Cabada, Lorena Saavedra, “Constant sign Green's function for simply supported beam equation”, in arXiv‎:

     The aim of this paper consists on the study of the following fourth-order operator: \\begin{equation}\\label{Ec::T4} T[M]\\,u(t)\\equiv u^{(4)}(t)+p_1(t)\\,u"'(t)+p_2(t)\\,u"(t)+M\\,u(t)\\,,\\ t\\in I \\equiv [a,b]\\,, \\end{equation} coupled with the two point boundary conditions: \\begin{equation}\\label{Ec::cf} u(a)=u(b)=u"(a)=u"(b)=0\\,. \\end{equation} So, we define the following space: \\begin{equation}\\label{Ec::esp} X=\\left\\lbrace u\\in C^4(I)\\quad\\mid\\quad u(a)=u(b)=u"(a)=u"(b)=0 \\right\\rbrace \\,. \\end{equation} Here ${\\displaystyle p_{1}\\in C^{3}(I)}$ and ${\\displaystyle p_{2}\\in C^{2}(I)}$. By assuming that the second order linear differential equation \\begin{equation}\\label{Ec::2or} L_2\\, u(t)\\equiv u"(t)+p_1(t)\\,u'(t)+p_2(t)\\,u(t)=0\\,,\\quad t\\in I, \\end{equation} is disconjugate on ${\\displaystyle I}$, we characterize the parameter's set where the Green's function related to operator ${\\displaystyle T[M]}$ in ${\\displaystyle X}$ is of constant sign on ${\\displaystyle I\\times I}$.